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Determining the fibrillar orientation of bast fibres with polarized light microscopy: the modified Herzog test (red plate test) explained.

Haugan E, Holst B - J Microsc (2013)

Bottom Line: The test has the reputation for never producing false results, but also for occasionally not working.However, so far, no proper justification has been provided in the literature that the 'no false results' assumption is really correct and it has also not been clear up till now, why the method sometimes does not work.We also provide an explanation for why the Herzog test sometimes does not work: According to our model, the Herzog test will not work if none of the three distinct layers in the secondary cell wall is significantly thicker than the others.

View Article: PubMed Central - PubMed

Affiliation: Department of Physics and Technology, University of Bergen, Bergen, Norway.

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(A) for various values of △ of the fibre. ϕ is fixed at 7.5°. (B)  for various values of fibrillar orientation ϕ. △ of fibre is fixed. Note that, the intensity minimum for all cases occurs at and .
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fig08: (A) for various values of △ of the fibre. ϕ is fixed at 7.5°. (B) for various values of fibrillar orientation ϕ. △ of fibre is fixed. Note that, the intensity minimum for all cases occurs at and .

Mentions: A plot of is shown in Figure 8, demonstrating how varies with ϕ and △ as well as α. As is clearly seen, attains its minimum for Thus, the main result from these calculations is that for all retardations and fibrillar angles of a fibre, minimum intensity is expected to occur at .


Determining the fibrillar orientation of bast fibres with polarized light microscopy: the modified Herzog test (red plate test) explained.

Haugan E, Holst B - J Microsc (2013)

(A) for various values of △ of the fibre. ϕ is fixed at 7.5°. (B)  for various values of fibrillar orientation ϕ. △ of fibre is fixed. Note that, the intensity minimum for all cases occurs at and .
© Copyright Policy - open-access
Related In: Results  -  Collection

License
Show All Figures
getmorefigures.php?uid=PMC4263192&req=5

fig08: (A) for various values of △ of the fibre. ϕ is fixed at 7.5°. (B) for various values of fibrillar orientation ϕ. △ of fibre is fixed. Note that, the intensity minimum for all cases occurs at and .
Mentions: A plot of is shown in Figure 8, demonstrating how varies with ϕ and △ as well as α. As is clearly seen, attains its minimum for Thus, the main result from these calculations is that for all retardations and fibrillar angles of a fibre, minimum intensity is expected to occur at .

Bottom Line: The test has the reputation for never producing false results, but also for occasionally not working.However, so far, no proper justification has been provided in the literature that the 'no false results' assumption is really correct and it has also not been clear up till now, why the method sometimes does not work.We also provide an explanation for why the Herzog test sometimes does not work: According to our model, the Herzog test will not work if none of the three distinct layers in the secondary cell wall is significantly thicker than the others.

View Article: PubMed Central - PubMed

Affiliation: Department of Physics and Technology, University of Bergen, Bergen, Norway.

Show MeSH