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N'-[(E)-(5-Bromo-2-hydroxy-phen-yl)(phen-yl)methyl-idene]-4-chloro-benzo-hydrazide.

Zheng CZ, Ji CY, Chang XL - Acta Crystallogr Sect E Struct Rep Online (2009)

Bottom Line: The Schiff base, C(20)H(14)BrClN(2)O(2), displays a trans conformation with respect to the C=N double bond.The aromatic rings at either end of the -C(=O)-NH-N=C- fragment are nearly parallel [dihedral angle = 3.4 (5)°].The hydr-oxy group forms an intra-molecular hydrogen bond to the imino N atom.

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ABSTRACT
The Schiff base, C(20)H(14)BrClN(2)O(2), displays a trans conformation with respect to the C=N double bond. The aromatic rings at either end of the -C(=O)-NH-N=C- fragment are nearly parallel [dihedral angle = 3.4 (5)°]. The hydr-oxy group forms an intra-molecular hydrogen bond to the imino N atom.

No MeSH data available.


The molecular structure of compound (I), showing the atom-numbering scheme. Displacement ellipsoids are drawn at the 30% probability level.
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Fap1: The molecular structure of compound (I), showing the atom-numbering scheme. Displacement ellipsoids are drawn at the 30% probability level.


N'-[(E)-(5-Bromo-2-hydroxy-phen-yl)(phen-yl)methyl-idene]-4-chloro-benzo-hydrazide.

Zheng CZ, Ji CY, Chang XL - Acta Crystallogr Sect E Struct Rep Online (2009)

The molecular structure of compound (I), showing the atom-numbering scheme. Displacement ellipsoids are drawn at the 30% probability level.
© Copyright Policy - open-access
Related In: Results  -  Collection

License
Show All Figures
getmorefigures.php?uid=PMC2977427&req=5

Fap1: The molecular structure of compound (I), showing the atom-numbering scheme. Displacement ellipsoids are drawn at the 30% probability level.
Bottom Line: The Schiff base, C(20)H(14)BrClN(2)O(2), displays a trans conformation with respect to the C=N double bond.The aromatic rings at either end of the -C(=O)-NH-N=C- fragment are nearly parallel [dihedral angle = 3.4 (5)°].The hydr-oxy group forms an intra-molecular hydrogen bond to the imino N atom.

View Article: PubMed Central - HTML - PubMed

ABSTRACT
The Schiff base, C(20)H(14)BrClN(2)O(2), displays a trans conformation with respect to the C=N double bond. The aromatic rings at either end of the -C(=O)-NH-N=C- fragment are nearly parallel [dihedral angle = 3.4 (5)°]. The hydr-oxy group forms an intra-molecular hydrogen bond to the imino N atom.

No MeSH data available.